Compound circuits often seem difficult to solve at first, but once you start solving small parts of the total circuit, everything starts to fall into place. In this compound circuit, you have an overall parallel arrangement. In one branch of the parallel circuit, you have a single resistor, in the other branch of the parallel circuit, you have two resistors in series.
The first step I always suggest doing is finding the total/equivalent resistance of the entire circuit. Once you have this piece to the puzzle, you can solve for the total current in the circuit. This information is often useful to check you solution. In this example, the current in each of the branches of the parallel circuit must add up to the total current in the circuit.
After finding the total resistance and current, I would then solve for the current in the branch containing the one resistor. Because this is a parallel arrangement and the voltage across this resistor is the same as the voltage of the battery, this is a simple calculation using ohms law. From there, you can solve for the current through the branch containing the two resistors in series. You know their equivalent resistance (simply the sum because they are arranged in series), and you know the voltage across the two resistors. Using the current through this branch, you can then solve for the voltage drop in each of the resistors.
As mentioned above, you last step should be to verify you results. The voltage drop in each of the two resistors in series must equal the total voltage. Also, the current in each of the branches must add up to the total current.
Have fun!